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Calculating reinforcement steel for an RCC column

Steel Calculation for a Column: Worked Example

Subhang Reddy3 min read

Columns are the steel-heaviest members per metre in a house frame. Working out one column precisely lets you check the bar bending schedule and the steel order.

Inputs (from the drawing)

ItemExample
Column size230 × 300 mm
Main bars6 nos, 12 mm
Ties8 mm @ 150 mm c/c
Storey height3.0 m
Clear cover40 mm
Lap50d = 600 mm

Main Bars

  • Length per bar = 3.0 + 0.6 lap = 3.6 m
  • Total = 6 × 3.6 = 21.6 m
  • Weight = 21.6 × 0.888 = 19.2 kg

Ties

Cutting length of one tie:

  • Inner width = 230 − 2 × 40 = 150 mm
  • Inner depth = 300 − 2 × 40 = 220 mm
  • Perimeter = 2 × (150 + 220) = 740 mm
  • Two 135° hooks: 2 × 10 × 8 = +160 mm
  • Bend deductions: three 90° (3 × 2 × 8 = 48) + two 135° (2 × 3 × 8 = 48) = −96 mm
  • Cutting length ≈ 804 mm

Number of ties: 3,000 ÷ 150 + 1 = 21

Weight: 21 × 0.804 × 0.395 = 6.7 kg

Many designs close the tie spacing near beam junctions, which adds a few ties.

Total

PartWeight
Main bars19.2 kg
Ties6.7 kg
Per column per floor≈ 26 kg

Multiply by the number of columns of this type on each floor, then add the footing starter bars and the length into the footing for the ground floor.

The Short Version

Bars × (height + lap) × kg/m, plus ties × cutting length × kg/m. A typical 230 × 300 mm house column carries about 26 kg of steel per floor.

Frequently Asked Questions

How do you calculate steel in a column?

Main bars: number × (height + lap) × kg per metre. Ties: work out one tie's cutting length from the column size, cover, hooks and bend deductions; multiply by the number of ties (height ÷ spacing + 1) and by kg per metre.

How much steel is in one column per floor?

For a 230 × 300 mm column with six 12 mm bars and 8 mm ties at 150 mm over a 3 m storey, about 26 kg including laps.

What lap length is used for column bars?

Often around 50 times the bar diameter as a site rule, so 600 mm for 12 mm bars, or as specified in the drawing.

How is the tie cutting length found?

Take the inner perimeter after cover, add two 135° hooks of 10 times the tie diameter, and subtract bend deductions — commonly 2d for each 90° bend and 3d for each 135° bend.

Should I add wastage?

Yes, about 2 to 5 percent for cutting, depending on how well cuts are planned around 12 metre bars.

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